water flows out through a circular pipe whose internal diameter is 2cm at the rate of 0.8m/s into a cylindrical tank, the radius of whose base is 40cm. by how much will the level rise in one and half hour?

Given, internal diametre of circular pipe = 2 cm

So, radius of circular pipe = 2/2 cm = 1cm

Since water flows at the rate of 0.8 m/s.

i.e., in 1 second it covers distance = 0.8 m = 80 cm

Given, radius of cylindrical tank (r) = 40 cm

Let the increase level of water = h cm

Since, water flows out through a circular pipe at the rate of 0.8 m/s into a cylindrical tank. So,

Hence, water rise by 270 m.

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